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42:15

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End

What data structure would you consider for looking up values in O(1) time?

I'd use a hash map to store the complement of each number...

Speaking...

Code Editor

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solution.pyoutput

1def two_sum(nums, target):

2 seen = {}

3 for i, num in enumerate(nums):

4 comp = target - num

5 if comp in seen:

6 return [seen[comp], i]

7 seen[num] = i

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Overall Score

+7 from last

Problem Solving85

Communication78

Code Quality90

Edge Cases65

Company Prep

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Google Prep

12 problems curated

Two SumEasy

LRU CacheMedium

Merge IntervalsMedium

Word LadderHard

2 of 12 practiced

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Walkthrough Mode

That's the right intuition! A hash map gives you O(1) lookups. Store each number's complement as you iterate — if you see it again, you've found your pair.

What about the space complexity of that approach?

O(n) — in the worst case you store every element before finding a match. That's the classic time-space tradeoff here.

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